J J Science Academy

1) An uniformly accelerated body travels a distance of 24 m in $5^{th}$ second of its motion and 44 m in $15^{th}$ sec of its motion. The acceleration of the particle will be
1) $1 m / s^2$ 2) $2 m / s^2$ 3) $4 m / s^2$ 4) $0.5 m / s^2$
Hint: $$s_n=u+\frac{1}{2} g(2n-1)$$ $$24=u+\frac{9a}{2}$$ $$44=u+\frac{29a}{2}$$ (ii) - (i) gives $$20=10a$$ $$a=2 m / s^2$$
2) A body, starting with some velocity, experiences uniform acceleration. It travels a distance of 20 m in $5^{th}$ second and 36 m in $9^{th}$ second. The acceleration of the particle (in $m / s^2$) is
1) 4 2) 2 3) 6 4) 8
Hint: $$s_n=u+\frac{1}{2} g(2n-1)$$ $$20=u+\frac{9a}{2}$$ $$36 = u + 17a$$ (ii) - (i) gives $$16=4a$$ $$a = 4 m/s^2$$
3) A particle starts moving along a straight line with velocity '$u$' and a constant acceleration '$a$', the initial velocity is
1) $1 m / s$ 2) $-1 m / s$ 3) $2 m / s$ 4) $-2 m / s$
Hint: $$s_9=u+\frac{1}{2}(4)[2(9)-1]$$ $$36=u+34$$ $$u=2 m / s$$
4) A particle starts moving along a straight line with velocity '$u$' and a constant acceleration '$a$', the distance it travels in $15^{th}$ second is
1) 54 m 2) 58 m 3) 60 m 4) 64 m
Hint: $$s_n=u+\frac{1}{2} g(2n-1)=2+\left[\frac{1}{2} \times 4 \times 29\right]=2+58=60 m$$