Paper Questions (Raw)
Q1. An uniformly accelerated body travels a distance of 24 m in (5^{\text {th }}) second of its motion and 44 m in (15^{\text {th }}) sec of its motion. The acceleration of the particle will be
1) (1 m / s^2)
2) (2 m / s^2)
3) (4 m / s^2)
4) (0.5 m / s^2)
Hint: $$s_n = u + \frac{1}{2} g(2n-1)$$
$$24 = u + \frac{9 a}{2}$$
$$44 = u + \frac{29 a}{2}$$
(ii) - (i) gives
$$20 = 10 a$$
$$a = 2 m / s^2$$
Q2. A body, starting with some velocity, experiences uniform acceleration. It travels a distance of 20 m in (5^{\text {th }}) second and 36 m in (9^{\text {th }}) second. The acceleration of the particle (m / s^2) is
Hint: $$s_n = u + \frac{1}{2} g(2n-1)$$
$$20 = u + \frac{9 a}{2}$$
36 = u + 17a(ii) - (i) gives16=4aa = 4 m/s2
Q3. A particle starts moving along a straight line with velocity '(u)' and a constant acceleration '(a)', the initial velocity is
1) (1 m / s)
2) (-1 m / s)
3) (2 m / s)
4) (-2 m / s)
Hint: $$s_9 = u + \frac{1}{2}(4)[2(9)-1]$$
$$36 = u + 34$$
$$u = 2 m / s$$
Q4. A particle starts moving along a straight line with velocity '(u)' and a constant acceleration '(a)', the distance it travels in (15^{\text {th }}) second is
1) 54 m
2) 58 m
3) 60 m
4) 64 m
Hint: $$s_n = u + \frac{1}{2} g(2n-1) = 2 + [\frac{1}{2} \times 4 \times 29] = 2 + 58 = 60 m$$